Y=5x^2+3x+4

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Solution for Y=5x^2+3x+4 equation: 



=5Y^2+3Y+4

We move all terms to the left:

-(5Y^2+3Y+4)=0

We get rid of parentheses

-5Y^2-3Y-4=0

a = -5; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·(-5)·(-4)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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